5k^2+38k=0

Solution for 5k^2+38k=0 equation:

5k^2+38k=0

a = 5; b = 38; c = 0;
Δ = b2-4ac
Δ = 382-4·5·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-38}{2*5}=\frac{-76}{10}
=-7+3/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+38}{2*5}=\frac{0}{10}
=0
$